Solve the equation $$ p^{2}-8 p+12=0 $$ by factoring. $$ p=\square $$ If there is more than 1 solution, separate the values with a comma. $$ $$ Next Question

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Solve the equation $$ p^{2}-8 p+12=0 $$ by factoring. $$ p=\square $$ If there is more than 1 solution, separate the values with a comma. $$ > $$ Next Question

UpStudy AI · Accepted Answer

1. Start with the equation:

$$
   p^2 - 8p + 12 = 0
   $$

2. Look for two numbers that multiply to $$12$$ and add to $$-8$$. These numbers are $$-2$$ and $$-6$$ because:

$$
   (-2) \times (-6) = 12 \quad \text{and} \quad (-2) + (-6) = -8
   $$

3. Rewrite the quadratic as a product of factors:

$$
   (p - 2)(p - 6) = 0
   $$

4. Use the Zero Product Property. Set each factor equal to zero:

- $$ p - 2 = 0 $$ which gives $$ p = 2 $$
   - $$ p - 6 = 0 $$ which gives $$ p = 6 $$

5. The solutions are:

$$
   p = 2, 6
   $$
$$ p = 2, 6 $$

Solve the equation \( p^{2}-8 p+12=0 \) by factoring. \( p=\square \) If there is more than 1 solution, separate the values with a comma. \( > \) Next Question

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