Hannah grows two corn plants. The first plant is \( 6 \frac{1}{4} \) feet tall The second plant is \( 4 \frac{6}{8} \) feet tall. How much taller is the first corn plant?

\(6 \frac{1}{4}\) can be written as an improper fraction by converting the whole and fractional parts: \[ 6 \frac{1}{4} = \frac{(6 \times 4) + 1}{4} = \frac{24 + 1}{4} = \frac{25}{4} \] Similarly, \(4 \frac{6}{8}\) is: \[ 4 \frac{6}{8} = 4 + \frac{6}{8} \] Simplify \(\frac{6}{8}\) by dividing the numerator and denominator by 2: \[ \frac{6}{8} = \frac{3}{4} \] So the second plant height is: \[ 4 \frac{6}{8} = 4 + \frac{3}{4} = \frac{(4 \times 4) + 3}{4} = \frac{16 + 3}{4} = \frac{19}{4} \] Now, subtract the height of the second plant from the first: \[ \frac{25}{4} - \frac{19}{4} = \frac{25 - 19}{4} = \frac{6}{4} \] Simplify \(\frac{6}{4}\): \[ \frac{6}{4} = \frac{3}{2} \] Convert \(\frac{3}{2}\) to a mixed number: \[ \frac{3}{2} = 1 \frac{1}{2} \] Thus, the first corn plant is \(1 \frac{1}{2}\) feet taller than the second corn plant.