Hannah grows two corn plants. The first plant is $$ 6 \frac{1}{4} $$ feet tall The second plant is $$ 4 \frac{6}{8} $$ feet tall. How much taller is the first corn plant?

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$$6 \frac{1}{4}$$ can be written as an improper fraction by converting the whole and fractional parts:

$$
6 \frac{1}{4} = \frac{(6 \times 4) + 1}{4} = \frac{24 + 1}{4} = \frac{25}{4}
$$

Similarly, $$4 \frac{6}{8}$$ is:

$$
4 \frac{6}{8} = 4 + \frac{6}{8}
$$

Simplify $$\frac{6}{8}$$ by dividing the numerator and denominator by 2:

$$
\frac{6}{8} = \frac{3}{4}
$$

So the second plant height is:

$$
4 \frac{6}{8} = 4 + \frac{3}{4} = \frac{(4 \times 4) + 3}{4} = \frac{16 + 3}{4} = \frac{19}{4}
$$

Now, subtract the height of the second plant from the first:

$$
\frac{25}{4} - \frac{19}{4} = \frac{25 - 19}{4} = \frac{6}{4}
$$

Simplify $$\frac{6}{4}$$:

$$
\frac{6}{4} = \frac{3}{2}
$$

Convert $$\frac{3}{2}$$ to a mixed number:

$$
\frac{3}{2} = 1 \frac{1}{2}
$$

Thus, the first corn plant is $$1 \frac{1}{2}$$ feet taller than the second corn plant.
The first corn plant is $$1 \frac{1}{2}$$ feet taller than the second corn plant.

Hannah grows two corn plants. The first plant is \( 6 \frac{1}{4} \) feet tall The second plant is \( 4 \frac{6}{8} \) feet tall. How much taller is the first corn plant?

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