$$ \begin{array}{l} ext { Evaluate the function at the indicated values. (If an answer is undefined, enter UNDEFINED.) }\ \begin{aligned} k(x) & =-x^{2}-5 x+6 ; \quad k(0), k(5), k(-5), k(\sqrt{5}), k(a+5), k(-x), k\left(x^{2} ight) \ k(0) & =6 \ k(5) & =-44 \ k(-5) & =6 \ k(\sqrt{5}) & =1-5 \sqrt{5} \ k(a+5) & =-a^{2}-15 a-44 \ k(-x) & =\square \ k\left(x^{2} ight) & =\square \end{aligned} \end{array} $$

Question

$$ \begin{array}{l} 	ext { Evaluate the function at the indicated values. (If an answer is undefined, enter UNDEFINED.) }\ \begin{aligned} k(x) & =-x^{2}-5 x+6 ; \quad k(0), k(5), k(-5), k(\sqrt{5}), k(a+5), k(-x), k\left(x^{2}ight) \ k(0) & =6 \ k(5) & =-44 \ k(-5) & =6 \ k(\sqrt{5}) & =1-5 \sqrt{5} \ k(a+5) & =-a^{2}-15 a-44 \ k(-x) & =\square \ k\left(x^{2}ight) & =\square \end{aligned} \end{array} $$

UpStudy AI · Accepted Answer

We are given the function k(x) = –x² – 5x + 6. To find k(–x) and k(x²):

1. For k(–x):
   Substitute –x into the function:
   k(–x) = –(–x)² – 5(–x) + 6.
   Since (–x)² = x², this becomes:
   k(–x) = –x² + 5x + 6.

2. For k(x²):
   Substitute x² into the function:
   k(x²) = –(x²)² – 5(x²) + 6.
   Since (x²)² = x⁴, this becomes:
   k(x²) = –x⁴ – 5x² + 6.

Thus, the answers are:
 k(–x) = –x² + 5x + 6 and k(x²) = –x⁴ – 5x² + 6.
k(–x) = –x² + 5x + 6 k(x²) = –x⁴ – 5x² + 6

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