For the function $$ f(x)=x^{2}+5 x-6 $$ solve the following. $$ f(x) \geq 0 $$

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Solve the equation $$ x^{2}+5x-6\geq 0 $$.
Solve the inequality by following steps:
- step0: Solve the inequality by testing the values in the interval:
  $$x^{2}+5x-6\geq 0$$
- step1: Rewrite the expression:
  $$x^{2}+5x-6=0$$
- step2: Factor the expression:
  $$\left(x-1ight)\left(x+6ight)=0$$
- step3: Separate into possible cases:
  $$\begin{align}&x-1=0\&x+6=0\end{align}$$
- step4: Solve the equation:
  $$\begin{align}&x=1\&x=-6\end{align}$$
- step5: Determine the test intervals:
  $$\begin{align}&x<-6\&-61\end{align}$$
- step6: Choose a value:
  $$\begin{align}&x_{1}=-7\&x_{2}=-3\&x_{3}=2\end{align}$$
- step7: Test the chosen value:
  $$\begin{align}&x<-6	extrm{ }	extrm{is the solution}\&-61	extrm{ }	extrm{is the solution}\end{align}$$
- step8: Include the critical value:
  $$\begin{align}&x\leq -6	extrm{ }	extrm{is the solution}\&x\geq 1	extrm{ }	extrm{is the solution}\end{align}$$
- step9: The final solution is $$x \in \left(-\infty,-6ight]\cup \left[1,+\inftyight):$$
  $$x \in \left(-\infty,-6ight]\cup \left[1,+\inftyight)$$
The solution to the inequality $$f(x) \geq 0$$ is $$x \in (-\infty, -6) \cup [1, \infty)$$.
The solution to $$ f(x) \geq 0 $$ is $$ x \leq -6 $$ or $$ x \geq 1 $$.

For the function solve the following.

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