Question
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Simplify. \( \frac{\frac{c^{2}-d^{2}}{c d}}{\frac{c-d}{d}} \) The simplified expression is \( \square \).

Ask by Hamilton Ball. in the United States
Mar 10,2025

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Tutor-Verified Answer

Answer

The simplified expression is \( \frac{c + d}{c} \).

Solution

1. Write the given expression: \[ \frac{\frac{c^{2} - d^{2}}{c d}}{\frac{c - d}{d}} \] 2. Rewrite the division as multiplication by the reciprocal: \[ \frac{c^{2} - d^{2}}{c d} \times \frac{d}{c - d} \] 3. Factor the numerator \( c^2 - d^2 \) as a difference of squares: \[ c^2 - d^2 = (c - d)(c + d) \] 4. Substitute the factorization into the expression: \[ \frac{(c - d)(c + d)}{c d} \times \frac{d}{c - d} \] 5. Cancel the common factor \( c - d \) from the numerator and denominator: \[ \frac{c + d}{c d} \times d \] 6. Multiply the remaining terms: \[ \frac{d(c + d)}{c d} = \frac{c + d}{c} \] The simplified expression is \( \frac{c+d}{c} \).

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Bonus Knowledge

To simplify the expression \( \frac{\frac{c^{2}-d^{2}}{c d}}{\frac{c-d}{d}} \), we can start by rewriting it: 1. The numerator \( c^{2}-d^{2} \) can be factored as \( (c-d)(c+d) \). So, we have: \[ \frac{(c-d)(c+d)}{cd} \] 2. Now, the denominator \( \frac{c-d}{d} \) can also be rewritten: \[ \frac{c-d}{d} = \frac{c-d}{1} \cdot \frac{1}{d} = \frac{c-d}{d} \] So our expression becomes: \[ \frac{(c-d)(c+d)}{cd} \div \frac{c-d}{d} \] 3. We can flip the denominator and multiply: \[ \frac{(c-d)(c+d)}{cd} \cdot \frac{d}{c-d} \] 4. Notice that \( c-d \) cancels out (assuming \( c \neq d \)): \[ \frac{(c+d)d}{c} = \frac{d(c+d)}{c} \] Thus, the simplified expression is: \[ \frac{d(c+d)}{c} \] So, the final answer is: \( \frac{d(c+d)}{c} \)

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