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2) \( \frac{\sin (u+v)}{\cos (u) \cos (v)}=\tan (u)+\tan (v) \)

Ask by Carrillo Logan. in the United States
Feb 25,2025

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Answer

\[ \frac{\sin (u + v)}{\cos (u) \cos (v)} = \tan (u) + \tan (v) \]

Solution

We start with the left-hand side:   LHS = sin(u + v) / [cos(u) cos(v)] Recall the sine addition formula:   sin(u + v) = sin u cos v + cos u sin v Substitute this into the numerator:   LHS = [sin u cos v + cos u sin v] / [cos(u) cos(v)] Now, split the fraction into two parts:   LHS = [sin u cos v] / [cos(u) cos(v)] + [cos u sin v] / [cos(u) cos(v)] Simplify each term separately:   The first term simplifies to sin u / cos u = tan u,   The second term simplifies to sin v / cos v = tan v. So, we obtain:   LHS = tan u + tan v Thus, we have verified that   sin(u + v) / [cos(u) cos(v)] = tan u + tan v.

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Mind Expander

Did you know that the equation \( \frac{\sin (u+v)}{\cos (u) \cos (v)}=\tan (u)+\tan (v) \) is a delightful mix of trigonometric identities? It stems from the sine addition formula, where \( \sin(u+v) = \sin(u)\cos(v) + \cos(u)\sin(v) \). When you divide both sides by \( \cos(u)\cos(v) \), you get to see the beauty of how the basic trigonometric functions interact! In practice, this identity helps simplify calculations in fields such as physics and engineering, particularly in wave mechanics or signal processing. By using this relation, engineers can break down complex waveforms into simpler components, making it easier to analyze and design circuits or signals. So, next time you’re tackling trig problems, remember that these identities are not just academic—they're tools you can wield in the real world!

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