15. \( \begin{array}{l}x+2 y=5 \\ 3 x+y=-8\end{array} \)
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To solve the system of equations \(x + 2y = 5\) and \(3x + y = -8\), we can use the substitution or elimination method. First, from the first equation, isolate \(x\): \[ x = 5 - 2y. \] Now, substitute \(x\) in the second equation: \[ 3(5 - 2y) + y = -8. \] This gives: \[ 15 - 6y + y = -8 \] \[ 15 - 5y = -8 \] \[ -5y = -23 \] \[ y = \frac{23}{5}. \] Now substitute \(y\) back into \(x = 5 - 2y\): \[ x = 5 - 2\left(\frac{23}{5}\right) = 5 - \frac{46}{5} = \frac{25}{5} - \frac{46}{5} = -\frac{21}{5}. \] Thus, the solution is \(x = -\frac{21}{5}\) and \(y = \frac{23}{5}\). Fun Fact: Did you know that systems of equations were used by ancient mathematicians, including the Chinese, who utilized a similar method called the "Nine Chapters on the Mathematical Art” to solve linear equations back in 200 AD? Real-World Application: Systems of equations are incredibly valuable in fields like economics, engineering, and even computer science. For instance, they can model supply and demand curves in economics, allowing businesses to optimize pricing based on various factors and responses from consumers!