QUESTION 3 3.1 Given the linear pattern: \( 7 ; 2 ;-3 ; \ldots \) 3.1.1 \( \quad \) Determine the general term, \( T_{n} \), of the linear pattern. \( \begin{array}{l}\text { 3.1.2 } \\ \begin{array}{l}\text { 3.1.3 } \\ \\ 3.2\end{array} \quad \text { Which term in the pattern has a value of }-138 \text { ? } \\ \text { Calculate the value of } x\end{array} \)
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The linear pattern you've shared (7; 2; -3; ...) has a common difference of -5. To find the general term \( T_{n} \), we can use the formula for the nth term of an arithmetic sequence: \[ T_{n} = a + (n - 1)d \] where \( a \) is the first term (7) and \( d \) is the common difference (-5). This gives us: \[ T_{n} = 7 + (n - 1)(-5) = 7 - 5(n - 1) \] \[ T_{n} = 12 - 5n \] --- Now, let’s tackle finding which term has a value of -138. We set the general term equal to -138: \[ 12 - 5n = -138 \] Solving for \( n \): \[ -5n = -138 - 12 \] \[ -5n = -150 \] \[ n = 30 \] So, the 30th term in the pattern has a value of -138.