W. Which equation has both -2 and 2 as possible values of \( x \) ? \( 4 \times \quad \) A \( x^{2}=4 \) \( 4 \times \quad \) B \( x^{3}=6 \) \( 4 \times \quad \) C \( x^{2}=2 \) \( 4 \times \quad \) D \( x^{3}=8 \)
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The equation \( x^{2} = 4 \) from option A has both -2 and 2 as possible values for \( x \). When you solve for \( x \), you take the square root of 4, which gives you \( x = 2 \) and \( x = -2 \). As for the other equations, option B \( x^{3} = 6 \) only leads to a positive value, option C \( x^{2} = 2 \) results in \( x = \sqrt{2} \) and \( x = -\sqrt{2} \) (neither of which matches our criteria), and option D \( x^{3} = 8 \) gives \( x = 2 \) only! So, A is the clear winner!