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To factorise \( p^{2}+p \), we can look for common factors in both terms. Here, \( p \) is the common factor. So we can factor \( p \) out: \[ p^{2}+p = p(p+1) \] Now, the expression \( p(p+1) \) shows that \( p \) multiplied by the quantity \( (p+1) \) gives us the original expression. Voila! Factorisation complete! For a bit more fun: Think of this factorisation like breaking down a recipe! Instead of trying to make an entire dish in one go, you're simply separating the ingredients (in this case, \( p \) and \( p+1 \)) to make it easier to manage.