Lines \( \leftarrow \quad \begin{array}{l}\text { Give the slope and the } y \text {-intercept of the line with the given equation. Then, graph } \\ \text { the linear equation. } 1 \text { of } 3\end{array} \) \( y=4 x+5 \)

1. The line is given in slope-intercept form: \[ y = 4x + 5 \] 2. In the equation \(\displaystyle y = mx + b\), the slope is given by \(\displaystyle m\) and the \(y\)-intercept by \(\displaystyle b\). 3. From the equation, the slope is \[ m = 4 \] and the \(y\)-intercept is \[ b = 5\quad \text{or the point } (0, 5). \] 4. To graph the line: - Start at the \(y\)-intercept, \((0, 5)\). - Since the slope is \(4\), which means \(\frac{4}{1}\), rise \(4\) units and run \(1\) unit to the right. This brings you to the point \((1, 9)\). - Continue using the slope to plot additional points if needed or draw a straight line through the points. 5. The final result: - **Slope:** \(\displaystyle 4\) - **\(y\)-intercept:** \(\displaystyle (0, 5)\) Graph these points on the Cartesian plane and draw a line through them to represent the equation.