The first four terms of \( n \)th term \( =n+6 \) is

To find the first four terms of the \( n \)th term defined by \( n + 6 \), we simply substitute \( n = 1, 2, 3, \) and \( 4 \): 1. When \( n = 1 \): \( 1 + 6 = 7 \) 2. When \( n = 2 \): \( 2 + 6 = 8 \) 3. When \( n = 3 \): \( 3 + 6 = 9 \) 4. When \( n = 4 \): \( 4 + 6 = 10 \) Therefore, the first four terms are 7, 8, 9, and 10. In playful terms, it's like starting a party at 7, and as more guests (n) arrive, the fun keeps multiplying with each new number joining in—first 7, then 8, party going strong at 9, and finally, it wraps up with a neat 10! What a number fiesta!