The graph of \( \sin (x+c) \) is shifted \( \frac{\pi}{5} \) units to the right compared to \( \sin x \). What is the value of \( c \) ? (1 point) \( c=\square \)

To shift the graph of \( \sin x \) to the right by \( \frac{\pi}{5} \) units, we can use the transformation property of sine functions. The general form of the sine function with a phase shift is \( \sin(x - d) \), where \( d \) is the shift to the right. Therefore, to shift \( \sin x \) to the right by \( \frac{\pi}{5} \), we have: \[ x + c = x - \frac{\pi}{5} \] From this equation, we can see that \( c \) must equal \( -\frac{\pi}{5} \). So the value of \( c \) is: \( c = -\frac{\pi}{5} \)