Answer
All four equations can be solved, with the solutions provided above.
Solution
Solve the quadratic equation by following steps:
- step0: Solve by factoring:
\(2x^{2}-x-6=0\)
- step1: Factor the expression:
\(\left(x-2\right)\left(2x+3\right)=0\)
- step2: Separate into possible cases:
\(\begin{align}&x-2=0\\&2x+3=0\end{align}\)
- step3: Solve the equation:
\(\begin{align}&x=2\\&x=-\frac{3}{2}\end{align}\)
- step4: Rewrite:
\(x_{1}=-\frac{3}{2},x_{2}=2\)
Solve the equation \( 3 x^{2}-2 x-5=0 \).
Solve the quadratic equation by following steps:
- step0: Solve by factoring:
\(3x^{2}-2x-5=0\)
- step1: Factor the expression:
\(\left(x+1\right)\left(3x-5\right)=0\)
- step2: Separate into possible cases:
\(\begin{align}&3x-5=0\\&x+1=0\end{align}\)
- step3: Solve the equation:
\(\begin{align}&x=\frac{5}{3}\\&x=-1\end{align}\)
- step4: Rewrite:
\(x_{1}=-1,x_{2}=\frac{5}{3}\)
Solve the equation \( x^{2}-9=0 \).
Solve the quadratic equation by following steps:
- step0: Solve using square roots:
\(x^{2}-9=0\)
- step1: Add or subtract both sides:
\(x^{2}=9\)
- step2: Simplify the expression:
\(x=\pm \sqrt{9}\)
- step3: Simplify the expression:
\(x=\pm 3\)
- step4: Separate into possible cases:
\(\begin{align}&x=3\\&x=-3\end{align}\)
- step5: Rewrite:
\(x_{1}=-3,x_{2}=3\)
Solve the equation \( x^{2}-x-6=0 \).
Solve the quadratic equation by following steps:
- step0: Solve by factoring:
\(x^{2}-x-6=0\)
- step1: Factor the expression:
\(\left(x-3\right)\left(x+2\right)=0\)
- step2: Separate into possible cases:
\(\begin{align}&x-3=0\\&x+2=0\end{align}\)
- step3: Solve the equation:
\(\begin{align}&x=3\\&x=-2\end{align}\)
- step4: Rewrite:
\(x_{1}=-2,x_{2}=3\)
Let's solve each of the equations step by step:
1. **Equation:** \( x^{2}-x-6=0 \)
- **Solutions:** \( x_{1}=-2 \), \( x_{2}=3 \)
2. **Equation:** \( x^{2}-9=0 \)
- **Solutions:** \( x_{1}=-3 \), \( x_{2}=3 \)
3. **Equation:** \( 3x^{2}-2x-5=0 \)
- **Solutions:** \( x_{1}=-1 \), \( x_{2}=\frac{5}{3} \) (or approximately \( 1.67 \))
4. **Equation:** \( 2x^{2}-x-6=0 \)
- **Solutions:** \( x_{1}=-\frac{3}{2} \) (or approximately \( -1.5 \)), \( x_{2}=2 \)
### Summary of Solutions:
- \( x^{2}-x-6=0 \) has solutions \( x = -2, 3 \)
- \( x^{2}-9=0 \) has solutions \( x = -3, 3 \)
- \( 3x^{2}-2x-5=0 \) has solutions \( x = -1, \frac{5}{3} \)
- \( 2x^{2}-x-6=0 \) has solutions \( x = -\frac{3}{2}, 2 \)
All of the given equations can be solved.
Answered by UpStudy AI and reviewed by a Professional Tutor

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