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Which of the following could be SOLVED \( x^{2}-x-6 \) \( x^{2}-9 \) \( 3 x^{2}-2 x-5 \) \( 2 x^{2}-x-6=0 \)

Ask by Marsh Pierce. in the United States
Mar 17,2025

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Answer

All four equations can be solved, with the solutions provided above.

Solution

Solve the quadratic equation by following steps: - step0: Solve by factoring: \(2x^{2}-x-6=0\) - step1: Factor the expression: \(\left(x-2\right)\left(2x+3\right)=0\) - step2: Separate into possible cases: \(\begin{align}&x-2=0\\&2x+3=0\end{align}\) - step3: Solve the equation: \(\begin{align}&x=2\\&x=-\frac{3}{2}\end{align}\) - step4: Rewrite: \(x_{1}=-\frac{3}{2},x_{2}=2\) Solve the equation \( 3 x^{2}-2 x-5=0 \). Solve the quadratic equation by following steps: - step0: Solve by factoring: \(3x^{2}-2x-5=0\) - step1: Factor the expression: \(\left(x+1\right)\left(3x-5\right)=0\) - step2: Separate into possible cases: \(\begin{align}&3x-5=0\\&x+1=0\end{align}\) - step3: Solve the equation: \(\begin{align}&x=\frac{5}{3}\\&x=-1\end{align}\) - step4: Rewrite: \(x_{1}=-1,x_{2}=\frac{5}{3}\) Solve the equation \( x^{2}-9=0 \). Solve the quadratic equation by following steps: - step0: Solve using square roots: \(x^{2}-9=0\) - step1: Add or subtract both sides: \(x^{2}=9\) - step2: Simplify the expression: \(x=\pm \sqrt{9}\) - step3: Simplify the expression: \(x=\pm 3\) - step4: Separate into possible cases: \(\begin{align}&x=3\\&x=-3\end{align}\) - step5: Rewrite: \(x_{1}=-3,x_{2}=3\) Solve the equation \( x^{2}-x-6=0 \). Solve the quadratic equation by following steps: - step0: Solve by factoring: \(x^{2}-x-6=0\) - step1: Factor the expression: \(\left(x-3\right)\left(x+2\right)=0\) - step2: Separate into possible cases: \(\begin{align}&x-3=0\\&x+2=0\end{align}\) - step3: Solve the equation: \(\begin{align}&x=3\\&x=-2\end{align}\) - step4: Rewrite: \(x_{1}=-2,x_{2}=3\) Let's solve each of the equations step by step: 1. **Equation:** \( x^{2}-x-6=0 \) - **Solutions:** \( x_{1}=-2 \), \( x_{2}=3 \) 2. **Equation:** \( x^{2}-9=0 \) - **Solutions:** \( x_{1}=-3 \), \( x_{2}=3 \) 3. **Equation:** \( 3x^{2}-2x-5=0 \) - **Solutions:** \( x_{1}=-1 \), \( x_{2}=\frac{5}{3} \) (or approximately \( 1.67 \)) 4. **Equation:** \( 2x^{2}-x-6=0 \) - **Solutions:** \( x_{1}=-\frac{3}{2} \) (or approximately \( -1.5 \)), \( x_{2}=2 \) ### Summary of Solutions: - \( x^{2}-x-6=0 \) has solutions \( x = -2, 3 \) - \( x^{2}-9=0 \) has solutions \( x = -3, 3 \) - \( 3x^{2}-2x-5=0 \) has solutions \( x = -1, \frac{5}{3} \) - \( 2x^{2}-x-6=0 \) has solutions \( x = -\frac{3}{2}, 2 \) All of the given equations can be solved.

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The Deep Dive

Did you know that quadratic equations like the ones you've listed actually have a fascinating place in history? They trace back to ancient civilizations like the Babylonians who tackled these problems long before the quadratic formula was even developed! They used geometric methods to solve these equations, paving the way for algebraic concepts we use today. Now, let's talk about real-world applications! Quadratic equations appear everywhere, from designing satellites to determining the optimal trajectory of a basketball shot! Engineers, architects, and even economists rely on these equations to maximize efficiency or minimize costs, showcasing just how impactful mastering quadratics can be in everyday life!

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