Question
\( \frac { ( 3 b ) ^ { 2 } + 12 a b ^ { 5 } } { 3 b } = \square b + \square a b \)
Ask by Ramirez Weber. in Canada
Mar 16,2025
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\(3b + 4ab\).
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Let's break this down! When simplifying the expression \( \frac { ( 3 b ) ^ { 2 } + 12 a b ^ { 5 } } { 3 b } \), first, we can rewrite the numerator: \( (3b)^2 = 9b^2 \). Now, substituting this back, we have \( \frac { 9b^2 + 12ab^5 } { 3b } \). Next, we can separate the terms: \[ \frac{9b^2}{3b} + \frac{12ab^5}{3b} = 3b + 4ab^4. \] Thus, the expression simplifies to \( 3b + 4ab^4 \). So, filling in the squares, we have: \( \square = 3 \) and \( 4 \).