Question
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derstanding: 1. Solve for \( x \) and graph: \( \frac{4 x}{3}-2 x<-\frac{6 x}{5}+7 \)

Ask by Marsh Nguyen. in South Africa
Mar 09,2025

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Tutor-Verified Answer

Answer

The solution to the inequality \( \frac{4x}{3}-2x<-\frac{6x}{5}+7 \) is \( x < \frac{105}{8} \). To graph it, draw the line \( x = \frac{105}{8} \) and shade the area to the left of this line.

Solution

Solve the equation \( \frac{4x}{3}-2x<-\frac{6x}{5}+7 \). Solve the inequality by following steps: - step0: Solve for \(x\): \(\frac{4x}{3}-2x<-\frac{6x}{5}+7\) - step1: Multiply both sides: \(\left(\frac{4x}{3}-2x\right)\times 15<\left(-\frac{6x}{5}+7\right)\times 15\) - step2: Multiply the terms: \(20x-30x<-18x+105\) - step3: Simplify: \(-10x<-18x+105\) - step4: Move the variable to the left side: \(-10x+18x<105\) - step5: Add the terms: \(8x<105\) - step6: Divide both sides: \(\frac{8x}{8}<\frac{105}{8}\) - step7: Divide the numbers: \(x<\frac{105}{8}\) The solution to the inequality \( \frac{4x}{3}-2x<-\frac{6x}{5}+7 \) is \( x < \frac{105}{8} \). To graph the inequality, we need to plot the line \( x = \frac{105}{8} \) and shade the region to the left of the line, as the inequality is less than. The graph will show the region where the inequality is true, which is all values of \( x \) less than \( \frac{105}{8} \).

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To solve the inequality \( \frac{4x}{3} - 2x < -\frac{6x}{5} + 7 \), let's first simplify the inequality. 1. Combine like terms: - Rewrite \( -2x \) as \( -\frac{6x}{3} \) to have a common denominator: \[ \frac{4x}{3} - \frac{6x}{3} < -\frac{6x}{5} + 7 \] - This simplifies to: \[ -\frac{2x}{3} < -\frac{6x}{5} + 7 \] 2. Now, eliminate the fractions by finding a common denominator, which is 15: - Multiply every term by 15: \[ -10x < -18x + 105 \] 3. Combine similar terms: \[ 8x < 105 \] 4. Divide both sides by 8: \[ x < \frac{105}{8} \quad \text{or} \quad x < 13.125 \] Now, to graph the solution on a number line, represent \( x < 13.125 \) with an open circle at 13.125 and shade to the left to indicate all the numbers less than that value. Happy graphing!

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