For a tundraiser, a group plans to sell \( x \) granola bars at \( \$ 1.25 \) each and \( y \) bottes of water at \( \$ 0.50 \) each. The group wants the revenue from the fundraiser to be at least \( \$ 150 \) Select the inequality that models the situation. A. \( 1.25 x+0.50 y>150 \) B. \( 1.25 x+0.50 y \geq 150 \) C. \( 1.25 x+0.50 y<150 \) D. \( 1.25 x+0.50 y \leq 150 \)

To model the fundraising revenue situation, you want to ensure that the total revenue from selling granola bars and bottles of water is at least $150. The correct inequality would reflect this condition, which means that the revenue can equal or exceed $150. Therefore, the ideal choice is: B. \( 1.25 x + 0.50 y \geq 150 \) By using this inequality, you're establishing a target that the group needs to hit or surpass for their fundraising efforts. Happy fundraising! For a bit of extra fun, imagine you're throwing a grand end-of-fundraiser party to celebrate hitting that revenue goal! Just like planning this event, crafting inequalities is about setting clear targets. And remember, every granola bar sold brings you closer to your dream party!