own below have a solution? Expl \[ \left\{\begin{array}{l}x+7 y=8 \\ 7 x-y=-2\end{array}\right. \]

Solve the system of equations \( x+7y=8;7x-y=-2 \). Solve the system of equations by following steps: - step0: Solve using the substitution method: \(\left\{ \begin{array}{l}x+7y=8\\7x-y=-2\end{array}\right.\) - step1: Solve the equation: \(\left\{ \begin{array}{l}x=8-7y\\7x-y=-2\end{array}\right.\) - step2: Substitute the value of \(x:\) \(7\left(8-7y\right)-y=-2\) - step3: Simplify: \(56-50y=-2\) - step4: Move the constant to the right side: \(-50y=-2-56\) - step5: Subtract the numbers: \(-50y=-58\) - step6: Change the signs: \(50y=58\) - step7: Divide both sides: \(\frac{50y}{50}=\frac{58}{50}\) - step8: Divide the numbers: \(y=\frac{29}{25}\) - step9: Substitute the value of \(y:\) \(x=8-7\times \frac{29}{25}\) - step10: Calculate: \(x=-\frac{3}{25}\) - step11: Calculate: \(\left\{ \begin{array}{l}x=-\frac{3}{25}\\y=\frac{29}{25}\end{array}\right.\) - step12: Check the solution: \(\left\{ \begin{array}{l}x=-\frac{3}{25}\\y=\frac{29}{25}\end{array}\right.\) - step13: Rewrite: \(\left(x,y\right) = \left(-\frac{3}{25},\frac{29}{25}\right)\) The solution to the system of equations is \( (x,y) = (-\frac{3}{25},\frac{29}{25}) \) or \( (x,y) = (-0.12,1.16) \).