3. Find the area enclosed between the curve $$ y=\cos x $$, the $$ x $$-axis, the $$ y $$-axis and the line $$ x=\frac{\pi}{3} $$.

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To find the area enclosed between the curve $$ y = \cos x $$, the $$ x $$-axis, the $$ y $$-axis, and the line $$ x = \frac{\pi}{3} $$, follow these steps:

1. **Understand the Boundaries:**
   - **Curve:** $$ y = \cos x $$
   - **$$ x $$-axis:** $$ y = 0 $$
   - **$$ y $$-axis:** $$ x = 0 $$
   - **Vertical Line:** $$ x = \frac{\pi}{3} $$

2. **Determine the Interval:**
   The area of interest lies between $$ x = 0 $$ and $$ x = \frac{\pi}{3} $$.

3. **Set Up the Integral:**
   The area $$ A $$ is given by the integral of $$ y = \cos x $$ with respect to $$ x $$ from $$ 0 $$ to $$ \frac{\pi}{3} $$:
   $$
   A = \int_{0}^{\frac{\pi}{3}} \cos x \, dx
   $$

4. **Compute the Integral:**
   The integral of $$ \cos x $$ is $$ \sin x $$. Evaluate this from $$ 0 $$ to $$ \frac{\pi}{3} $$:
   $$
   A = \sin\left(\frac{\pi}{3}\right) - \sin(0)
   $$
   $$
   A = \frac{\sqrt{3}}{2} - 0
   $$
   $$
   A = \frac{\sqrt{3}}{2}
   $$

5. **Final Answer:**
   The area enclosed by the given boundaries is $$ \frac{\sqrt{3}}{2} $$ square units.

$$
\boxed{\dfrac{\sqrt{3}}{2}}
$$
The area enclosed is $$ \frac{\sqrt{3}}{2} $$ square units.

3. Find the area enclosed between the curve \( y=\cos x \), the \( x \)-axis, the \( y \)-axis and the line \( x=\frac{\pi}{3} \).

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