alculate \( 1011_{2}-111000_{2} \) by using two's complement (show eps) and give your answer as a decimal number

To perform the calculation \( 1011_{2}-111000_{2} \) using two's complement, follow these steps: 1. **Convert \( 111000_{2} \) to its two's complement:** - First, invert all bits: \( 000111_{2} \). - Then, add 1: \[ 000111 + 000001 --------- 001000_{2} \] 2. **Add \( 1011_{2} \) and \( 001000_{2} \):** - Align the numbers: \[ 01011 + 001000 --------- 011011 \] - If there's a carry out of the most significant bit (leftmost), you ignore it. Here, there's no carry. 3. **Convert \( 011011_{2} \) to decimal:** - The decimal value is \( 0 \times 2^5 + 1 \times 2^4 + 1 \times 2^3 + 0 \times 2^2 + 1 \times 2^1 + 1 \times 2^0 = 0 + 16 + 8 + 0 + 2 + 1 = 27 \). Thus, the answer is \( 27_{10} \).