2. © De que numere es $$ 45 \mathrm{el} 20 \%= $$ $$ \qquad $$ 21 el $$ 28 \%= $$ $$ \qquad $$ 12.48 el $$ 104 \%= $$ $$ \qquad $$ 38.08 el $$ 56 \%= $$ $$ \qquad $$ 135 el $$ 45 \%= $$ $$ \qquad $$ 0.8 el $$ 3.2 \%= $$ $$ \qquad $$ 63 el $$ 200 \%= $$ $$ \qquad $$ 1.8 el $$ 36 \%= $$ $$ \qquad $$ 60 el 4\% = $$ \qquad $$ 27 el $$ 9 \%= $$ $$ \qquad $$

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1. Resolver $$45 = 20\%\cdot N$$.  
   Sabemos que $$20\% = 0.20$$. Entonces:  
   $$
   N=\frac{45}{0.20}=225
   $$

2. Resolver $$21 = 28\%\cdot N$$.  
   Como $$28\% = 0.28$$, se tiene:  
   $$
   N=\frac{21}{0.28}=75
   $$

3. Resolver $$12.48 = 104\%\cdot N$$.  
   Dado que $$104\% = 1.04$$, se obtiene:  
   $$
   N=\frac{12.48}{1.04}=12
   $$

4. Resolver $$38.08 = 56\%\cdot N$$.  
   Con $$56\% = 0.56$$, se tiene:  
   $$
   N=\frac{38.08}{0.56}=68
   $$

5. Resolver $$135 = 45\%\cdot N$$.  
   Ya que $$45\% = 0.45$$, la ecuación es:  
   $$
   N=\frac{135}{0.45}=300
   $$

6. Resolver $$0.8 = 3.2\%\cdot N$$.  
   Notamos que $$3.2\% = 0.032$$, por lo tanto:  
   $$
   N=\frac{0.8}{0.032}=25
   $$

7. Resolver $$63 = 200\%\cdot N$$.  
   Siendo $$200\% = 2$$, se tiene:  
   $$
   N=\frac{63}{2}=31.5
   $$

8. Resolver $$1.8 = 36\%\cdot N$$.  
   Con $$36\% = 0.36$$, se obtiene:  
   $$
   N=\frac{1.8}{0.36}=5
   $$

9. Resolver $$60 = 4\%\cdot N$$.  
   Como $$4\% = 0.04$$, se calcula:  
   $$
   N=\frac{60}{0.04}=1500
   $$

10. Resolver $$27 = 9\%\cdot N$$.  
    Dado que $$9\% = 0.09$$, se tiene:  
    $$
    N=\frac{27}{0.09}=300
    $$
1. $$ N = 225 $$ 2. $$ N = 75 $$ 3. $$ N = 12 $$ 4. $$ N = 68 $$ 5. $$ N = 300 $$ 6. $$ N = 25 $$ 7. $$ N = 31.5 $$ 8. $$ N = 5 $$ 9. $$ N = 1500 $$ 10. $$ N = 300 $$

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