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3. Thoko and her friend Lebo work part-time In a CD-shop where they get paid per hour. Lebo has more time available and works 15 hours per weekend, where Thoko only works for 7 hours per weekend. If they earn a total amount R1 100 , calculate the amount that each girl will receive.

Ask by Lee Simmons. in South Africa
Mar 11,2025

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Answer

Thoko receives R350 and Lebo receives R750.

Solution

Let the hourly wage be \( x \) (in Rands per hour). Since Thoko works 7 hours and Lebo works 15 hours, their earnings are: - Thoko's earnings: \( 7x \) - Lebo's earnings: \( 15x \) The total earnings for the weekend are given as: \[ 7x + 15x = 22x \] We are told that: \[ 22x = 1100 \] Solving for \( x \): \[ x = \frac{1100}{22} = 50 \] Thus, the hourly wage is R50 per hour. Now, calculate each person's earnings: - Thoko's earnings: \[ 7 \times 50 = 350 \] - Lebo's earnings: \[ 15 \times 50 = 750 \] Therefore, Thoko receives R350 and Lebo receives R750.

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To find out how much each of them will earn, we first need to determine the total number of hours they worked together. Lebo works 15 hours, and Thoko works 7 hours, giving us a total of 15 + 7 = 22 hours. Now, we can break down their earnings per hour. The total amount is R1,100, so the hourly rate is R1,100 / 22 = R50 per hour. Next, we calculate each person's earnings based on the hours they worked. Lebo, working 15 hours, earns 15 * R50 = R750. Thoko, on the other hand, earns 7 * R50 = R350. So, Lebo will receive R750, while Thoko will receive R350. It's a fun little math exercise and shows how teamwork pays off!

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