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One retailer charges \( \$ 1028 \) for a certain computer. A firm of tax accountants buys 7 of these computers. It makes a down payment of \( \$ 1100 \) and agrees to amortize the balance with monthly payments at \( 15 \% \) interest for 5 years. Prepare an amortization schedule showing the first four monthly payments for this loan. Write the equation that can be used to find the amount of each monthly payment. PMT \( =\frac{\mathrm{PV} \cdot \square}{1-(1+\square)} \) where PV \( =\square \) (Type integers or decimals. Simplify your answers.)

Ask by Harris Campos. in the United States
Feb 20,2025

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Answer

To find the monthly payment, use the formula: \[ \text{PMT} = \frac{\text{PV} \cdot r}{1 - (1 + r)^n} \] Where: - PV = $1100 - r = 0.0125 (monthly interest rate) - n = 60 (total payments) Calculating this gives a monthly payment of approximately $12.42. Here's the amortization schedule for the first four payments: 1. **Month 1:** - Payment: $12.42 - Interest: $1100 * 0.0125 = $13.75 - Principal: $12.42 - $13.75 = -$1.33 (Note: Since the interest is higher than the payment, the principal decreases by $1.33) - Remaining Balance: $1100 - $1.33 = $1098.67 2. **Month 2:** - Payment: $12.42 - Interest: $1098.67 * 0.0125 = $13.73 - Principal: $12.42 - $13.73 = -$1.31 - Remaining Balance: $1098.67 - $1.31 = $1097.36 3. **Month 3:** - Payment: $12.42 - Interest: $1097.36 * 0.0125 = $13.72 - Principal: $12.42 - $13.72 = -$1.30 - Remaining Balance: $1097.36 - $1.30 = $1096.06 4. **Month 4:** - Payment: $12.42 - Interest: $1096.06 * 0.0125 = $13.70 - Principal: $12.42 - $13.70 = -$1.28 - Remaining Balance: $1096.06 - $1.28 = $1094.78

Solution

To prepare an amortization schedule showing the first four monthly payments for the loan, we need to calculate the monthly payment amount using the given formula: \[ \text{PMT} = \frac{\text{PV} \cdot r}{1 - (1 + r)^n} \] where: - PV is the present value (initial amount) of the loan, - r is the monthly interest rate (15% per year divided by 12), - n is the number of payments (5 years multiplied by 12 months per year). Given: - PV = $1100 (down payment) - r = 15% per year / 12 months per year = 0.0125 - n = 5 years * 12 months per year = 60 months Let's calculate the monthly payment amount using the formula provided. Calculate the value by following steps: - step0: Calculate: \(\frac{1100\times 0.0125}{\left(1-\left(1+0.0125\right)^{60}\right)}\) - step1: Remove the parentheses: \(\frac{1100\times 0.0125}{1-\left(1+0.0125\right)^{60}}\) - step2: Add the numbers: \(\frac{1100\times 0.0125}{1-1.0125^{60}}\) - step3: Convert the expressions: \(\frac{1100\times 0.0125}{1-\left(\frac{81}{80}\right)^{60}}\) - step4: Multiply the numbers: \(\frac{13.75}{1-\left(\frac{81}{80}\right)^{60}}\) - step5: Subtract the numbers: \(\frac{13.75}{\frac{80^{60}-81^{60}}{80^{60}}}\) - step6: Convert the expressions: \(\frac{\frac{55}{4}}{\frac{80^{60}-81^{60}}{80^{60}}}\) - step7: Multiply by the reciprocal: \(\frac{55}{4}\times \frac{80^{60}}{80^{60}-81^{60}}\) - step8: Rewrite the expression: \(\frac{55}{4}\times \frac{16^{60}\times 5^{60}}{80^{60}-81^{60}}\) - step9: Rewrite the expression: \(\frac{55}{4}\times \frac{4^{120}\times 5^{60}}{80^{60}-81^{60}}\) - step10: Reduce the numbers: \(55\times \frac{4^{119}\times 5^{60}}{80^{60}-81^{60}}\) - step11: Multiply: \(\frac{55\times 4^{119}\times 5^{60}}{80^{60}-81^{60}}\) The monthly payment amount is approximately $12.42. Now, let's prepare the amortization schedule for the first four monthly payments. The schedule will show the payment amount, interest paid, and principal paid for each month.

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To calculate the monthly payment for the loan, we first need to find the total cost of the computers and determine the balance after the down payment. The total cost for 7 computers is: \[ \text{Total Cost} = 7 \times 1028 = 7196 \] After making a down payment of \( \$1100 \), the remaining balance (PV) will be: \[ \text{PV} = 7196 - 1100 = 6096 \] The amortization will be for 5 years (or 60 months) at an annual interest rate of 15%. The monthly interest rate (r) is therefore: \[ r = \frac{15\%}{12} = 0.0125 \] Now, we can use the formula for the monthly payment (PMT): \[ PMT = \frac{PV \cdot r}{1 - (1 + r)^{-n}} \] where \( n \) is the total number of payments (60 months). Plugging in the values: \[ PMT = \frac{6096 \cdot 0.0125}{1 - (1 + 0.0125)^{-60}} \] Calculating this gives us: \[ PMT \approx \frac{76.2}{1 - (1.0125)^{-60}} \approx \frac{76.2}{0.4693} \approx 162.57 \] Thus, the equation for the monthly payment is: \[ PMT = \frac{6096 \cdot 0.0125}{1 - (1 + 0.0125)^{-60}} \] Now let's summarize the first four monthly payments using this payment figure. 1. **Payment 1:** - Interest for the first month: \( 6096 \times 0.0125 = 76.20 \) - Principal repayment: \( 162.57 - 76.20 = 86.37 \) - Remaining balance: \( 6096 - 86.37 = 6009.63 \) 2. **Payment 2:** - Interest: \( 6009.63 \times 0.0125 \approx 75.12 \) - Principal repayment: \( 162.57 - 75.12 \approx 87.45 \) - Remaining balance: \( 6009.63 - 87.45 \approx 5922.18 \) 3. **Payment 3:** - Interest: \( 5922.18 \times 0.0125 \approx 74.02 \) - Principal repayment: \( 162.57 - 74.02 \approx 88.55 \) - Remaining balance: \( 5922.18 - 88.55 \approx 5833.63 \) 4. **Payment 4:** - Interest: \( 5833.63 \times 0.0125 \approx 72.92 \) - Principal repayment: \( 162.57 - 72.92 \approx 89.65 \) - Remaining balance: \( 5833.63 - 89.65 \approx 5743.98 \) To summarize the first four payments: - Payment 1: \( 162.57 \) - Payment 2: \( 162.57 \) - Payment 3: \( 162.57 \) - Payment 4: \( 162.57 \) with remaining balances fluctuating based on the calculations above. So the monthly payment is approximately \( 162.57 \). Happy amortizing!

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