Problems 9-10: Solve each equation. Show your thinking. \( \begin{array}{ll}9 .-4(r+2)=4(2-2 r) & \text { 10. } 1.3+6 d=2.7-8 d\end{array} \)
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Let's dive into solving these equations step by step! For equation 9, \(-4(r+2) = 4(2-2r)\): First, distribute on both sides: \(-4r - 8 = 8 - 8r\). Next, add \(8r\) to both sides: \(-4r + 8r - 8 = 8\) which simplifies to \(4r - 8 = 8\). Now, add 8 to both sides: \(4r = 16\). Finally, divide by 4: \(r = 4\). Now for equation 10, \(1.3 + 6d = 2.7 - 8d\): First, let's move the \(8d\) to the left by adding \(8d\): \(1.3 + 14d = 2.7\). Next, subtract \(1.3\) from both sides: \(14d = 1.4\). Finally, divide by 14: \(d = 0.1\). So, \(r = 4\) for equation 9 and \(d = 0.1\) for equation 10! Happy solving!