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For the function \( f(x)=x^{4}-3 x^{3}+x^{2}+2 x+83 \) use long division to determine whether \( x+4 \) is a factor of \( f(x) \).

Ask by Patel Hilton. in the United States
Mar 20,2025

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\( x+4 \) is not a factor of \( f(x) \).

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Mind Expander

To determine whether \( x + 4 \) is a factor of \( f(x) = x^4 - 3x^3 + x^2 + 2x + 83 \), we'll use polynomial long division to divide \( f(x) \) by \( x + 4 \). 1. **Setup:** Write down \( f(x) \) as the dividend and \( x + 4 \) as the divisor. 2. **First Division:** - Divide the leading term of \( f(x) \), which is \( x^4 \), by the leading term of \( x + 4 \), which is \( x \). - This gives \( x^3 \). Multiply \( x^3 \) by \( x + 4 \): \[ x^3(x + 4) = x^4 + 4x^3 \] - Subtract this from \( f(x) \): \[ f(x) - (x^4 + 4x^3) = (-3x^3 - 4x^3) + x^2 + 2x + 83 = -7x^3 + x^2 + 2x + 83 \] 3. **Second Division:** - Divide the new leading term \(-7x^3\) by \(x\): \[ -7x^2 \] - Multiply \(-7x^2\) by \(x + 4\): \[ -7x^2(x + 4) = -7x^3 - 28x^2 \] - Subtract: \[ (-7x^3 + x^2 + 2x + 83) - (-7x^3 - 28x^2) = (1 + 28)x^2 + 2x + 83 = 29x^2 + 2x + 83 \] 4. **Third Division:** - Divide \(29x^2\) by \(x\): \[ 29x \] - Multiply \(29x\) by \(x + 4\): \[ 29x(x + 4) = 29x^2 + 116x \] - Subtract: \[ (29x^2 + 2x + 83) - (29x^2 + 116x) = 2x - 116x + 83 = -114x + 83 \] 5. **Fourth Division:** - Divide \(-114x\) by \(x\): \[ -114 \] - Multiply \(-114\) by \(x + 4\): \[ -114(x + 4) = -114x - 456 \] - Subtract: \[ (-114x + 83) - (-114x - 456) = 83 + 456 = 539 \] After performing the long division, we are left with the remainder 539. Since the remainder is not zero, \( x + 4 \) is not a factor of \( f(x) \).

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