2.1.1. \( (580-68) \times 7 \times 0 \) 2.1.2. \( -10+4(16-6) \div 2+4 \times 10 \)

**2.1.1. Calculation of \( (580-68) \times 7 \times 0 \)** 1. Calculate the subtraction inside the parentheses: \[ 580 - 68 = 512 \] 2. Multiply by 7: \[ 512 \times 7 = 3584 \] 3. Multiply by 0: \[ 3584 \times 0 = 0 \] Thus, the final result is \( 0 \). --- **2.1.2. Calculation of \( -10+4(16-6) \div 2+4 \times 10 \)** 1. Calculate the subtraction inside the parentheses: \[ 16 - 6 = 10 \] 2. Substitute the result in the expression: \[ -10 + 4 \times 10 \div 2 + 4 \times 10 \] 3. Perform the multiplications and division from left to right: - First, multiply: \[ 4 \times 10 = 40 \] - Then, divide: \[ 40 \div 2 = 20 \] - Also, multiply: \[ 4 \times 10 = 40 \] 4. Combine the results: \[ -10 + 20 + 40 \] 5. Add together step by step: - First addition: \[ -10 + 20 = 10 \] - Second addition: \[ 10 + 40 = 50 \] Thus, the final result is \( 50 \).