A fair die is rolled 6 times. What is the probability that a 6 is obtained on at least one of the rolls? Round your answer to three decimal places.

To determine the probability of rolling at least one 6 in six rolls of a fair die, we can first calculate the complementary probability: that is, the probability of not rolling a 6 in all six rolls. The probability of not rolling a 6 on a single roll is \( \frac{5}{6} \). Therefore, the probability of not rolling a 6 in six rolls is \( \left(\frac{5}{6}\right)^6 \). Now, we calculate this value: \[ \left(\frac{5}{6}\right)^6 \approx 0.3349 \] Next, we find the probability of rolling at least one 6 by subtracting this result from 1: \[ P(\text{at least one 6}) = 1 - P(\text{no 6s}) \approx 1 - 0.3349 \approx 0.6651 \] Finally, rounding to three decimal places, the probability of obtaining a 6 on at least one of the rolls is: \[ \boxed{0.665} \]