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20. \( P( \) Drawing a Queen \( )=\frac{4}{52} \) What is the probability of not drawing a Queen? 21. If \( P(A)=\frac{10}{17} \), what is the \( P(A \) does not occur)?

Ask by Herrera Li. in the United States
Feb 26,2025

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20. The probability of not drawing a Queen is 12/13. 21. The probability of A not occurring is 7/17.

Solution

20. The probability of drawing a Queen is 4/52. Therefore, the probability of not drawing a Queen is 1 - 4/52 = 48/52, which simplifies to 12/13. 21. If P(A) = 10/17, then the probability of A not occurring is 1 - 10/17 = 7/17.

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The probability of not drawing a Queen can be calculated by subtracting the probability of drawing a Queen from 1. Since \( P(\text{Queen}) = \frac{4}{52} = \frac{1}{13} \), the probability of not drawing a Queen is \( 1 - \frac{1}{13} = \frac{12}{13} \). So, you have a 12 out of 13 chance of drawing something other than a Queen—pretty good odds! For the second question, the probability of event \( A \) not occurring can be found by using the formula \( P(A') = 1 - P(A) \). Since \( P(A) = \frac{10}{17} \), you would get \( P(A') = 1 - \frac{10}{17} = \frac{7}{17} \). Thus, there's a 7 in 17 chance that event \( A \) doesn’t happen, so keep your fingers crossed!

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