3.1 Draw neat graphs on Annexure \( A \) of a line through the points \( P(-1: 0) \) and \( 3(1: 2) \) and a line through the points \( R(1: 4) \) and \( S(-1: 2) \) 3.3 Wetermine the equations of the straight lines \( P Q \) and \( R S \) 3.4 Hence complete the statement __ lines have _ gradients.
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Bonus Knowledge
To visualize the action, let’s sketch! For the first line through points \( P(-1, 0) \) and \( Q(3, 2) \), plot both points on the coordinate plane. Connect them with a straight line, making sure it rises gently from left to right. Now for the second line through \( R(1, 4) \) and \( S(-1, 2) \), do the same, but this one will have a steeper downward slope. You’ll see how these two lines interact in this fun visual adventure! Now, the equations of the straight lines are where the math magic happens! For line \( PQ \), using the slope formula \( m = \frac{y_2 - y_1}{x_2 - x_1} \), we find the slope to be \(\frac{2 - 0}{3 - (-1)} = \frac{2}{4} = \frac{1}{2}\). Thus, its equation simplifies down to \( y = \frac{1}{2}x + \frac{1}{2} \). For line \( RS \), here, \( m = \frac{2 - 4}{-1 - 1} = \frac{-2}{-2} = 1\), leading to the equation \( y = x + 3 \). Hence, we can complete the statement: _ Two lines have different gradients!