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Use properties of logarithms to expand the logarithmic expression as much as possible. Where possible, evaluate logarithmic expressions without using a calculator. \( \log _{5}(2 \cdot 13) \)

Ask by Grant Turner. in the United States
Mar 21,2025

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\[ \log_{5}(2) + \log_{5}(13) \]

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To expand the logarithmic expression \( \log_{5}(2 \cdot 13) \), we can use the product property of logarithms, which states that: \[ \log_{b}(mn) = \log_{b}(m) + \log_{b}(n) \] Applying this property to our expression: \[ \log_{5}(2 \cdot 13) = \log_{5}(2) + \log_{5}(13) \] Now, we have expanded the logarithmic expression as much as possible. Next, we can evaluate \( \log_{5}(2) \) and \( \log_{5}(13) \) without using a calculator. However, since these values do not correspond to simple fractions or integers, we will leave them in logarithmic form. Thus, the final expanded expression is: \[ \log_{5}(2) + \log_{5}(13) \]

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To expand the expression \( \log_{5}(2 \cdot 13) \), we can use the product property of logarithms, which states that \( \log_b(m \cdot n) = \log_b(m) + \log_b(n) \). Applying this property: \[ \log_{5}(2 \cdot 13) = \log_{5}(2) + \log_{5}(13) \] Unfortunately, we cannot simplify \( \log_{5}(2) \) or \( \log_{5}(13) \) into a numeric form without a calculator, so we leave these logarithms in their expanded form. Hence, your final expanded expression is \[ \log_{5}(2) + \log_{5}(13). \] Remember, if you're ever in a pinch and need to estimate values, knowing that \( \log_{5}(2) \) is less than 1 and \( \log_{5}(13) \) is greater than 1 can help you get a rough idea of the size of the result!

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