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Use properties of logarithms to expand the logarithmic expression as much as possible. Evaluate logarithmic expressions without using a calculator if possible. In \( \left[\frac{x^{4} \sqrt{x^{2}+4}}{(x+4)^{4}}\right] \) \( \ln \left[\frac{x^{4} \sqrt{x^{2}+4}}{(x+4)^{4}}\right]=\square \)

Ask by Macdonald Pena. in the United States
Mar 21,2025

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Answer

\[ \ln \left[\frac{x^{4} \sqrt{x^{2}+4}}{(x+4)^{4}}\right] = 4\ln(x) + \frac{1}{2}\ln\left(x^2+4\right) - 4\ln(x+4) \]

Solution

1. Begin with the expression \[ \ln \left[\frac{x^{4} \sqrt{x^{2}+4}}{(x+4)^{4}}\right]. \] 2. Use the logarithmic property for division: \[ \ln \left(\frac{A}{B}\right) = \ln(A) - \ln(B). \] Thus, \[ \ln \left[\frac{x^{4} \sqrt{x^{2}+4}}{(x+4)^{4}}\right] = \ln\left(x^4 \sqrt{x^2+4}\right) - \ln\left((x+4)^4\right). \] 3. Use the logarithmic property for multiplication in the numerator: \[ \ln(AB) = \ln(A) + \ln(B). \] So, \[ \ln\left(x^4 \sqrt{x^2+4}\right) = \ln\left(x^4\right) + \ln\left(\sqrt{x^2+4}\right). \] 4. Apply the power rule for logarithms: \[ \ln\left(x^4\right) = 4\ln(x) \quad \text{and} \quad \ln\left((x+4)^4\right) = 4\ln(x+4). \] 5. Recall that a square root can be written as a power of one-half: \[ \sqrt{x^2+4} = (x^2+4)^{\frac{1}{2}}, \] which implies \[ \ln\left(\sqrt{x^2+4}\right) = \frac{1}{2}\ln\left(x^2+4\right). \] 6. Combine all of the results: \[ \ln \left[\frac{x^{4} \sqrt{x^{2}+4}}{(x+4)^{4}}\right] = 4\ln(x) + \frac{1}{2}\ln\left(x^2+4\right) - 4\ln(x+4). \] Thus, the fully expanded logarithmic expression is \[ \boxed{4\ln(x) + \frac{1}{2}\ln\left(x^2+4\right) - 4\ln(x+4)}. \]

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Let's expand the logarithmic expression \( \ln \left[\frac{x^{4} \sqrt{x^{2}+4}}{(x+4)^{4}}\right] \) using the properties of logarithms. First, we can use the property \( \ln \left(\frac{a}{b}\right) = \ln(a) - \ln(b) \): \[ \ln \left[\frac{x^{4} \sqrt{x^{2}+4}}{(x+4)^{4}}\right] = \ln(x^{4} \sqrt{x^{2}+4}) - \ln((x+4)^{4}). \] Next, we can break down \( \ln(x^{4} \sqrt{x^{2}+4}) \) further: \[ \ln(x^{4} \sqrt{x^{2}+4}) = \ln(x^{4}) + \ln(\sqrt{x^{2}+4}). \] Using the property \( \ln(a^{b}) = b \ln(a) \): \[ \ln(x^{4}) = 4\ln(x) \quad \text{and} \quad \ln(\sqrt{x^{2}+4}) = \frac{1}{2}\ln(x^{2}+4). \] Now, we handle the denominator: \[ \ln((x+4)^{4}) = 4\ln(x+4). \] Putting it all together, we have: \[ \ln \left[\frac{x^{4} \sqrt{x^{2}+4}}{(x+4)^{4}}\right] = 4\ln(x) + \frac{1}{2}\ln(x^{2}+4) - 4\ln(x+4). \] So the final answer is: \[ \ln \left[\frac{x^{4} \sqrt{x^{2}+4}}{(x+4)^{4}}\right] = 4 \ln(x) + \frac{1}{2} \ln(x^{2}+4) - 4 \ln(x+4). \]

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