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1) \( \begin{array}{l}\text { Si } f(x)=x^{2}-3 x+2 \text {, e volor de }(1) \text { es } \\ f(x)=x^{2}-3 x+2\end{array} \)

Ask by Barker Long. in Mexico
Mar 13,2025

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El valor de \( f(1) \) es \( 0 \).

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Para encontrar el valor de \( f(1) \), simplemente sustituimos \( x \) por 1 en la función: \[ f(1) = 1^{2} - 3(1) + 2 = 1 - 3 + 2 = 0. \] Así que el valor de \( f(1) \) es 0. ¡Y ahí tienes una bonita parábola que tiene su punto en cero cuando \( x = 1 \)! Para agregar un dato curioso, esta función cuadrática tiene dos raíces o valores donde cruza el eje \( x \). Al resolver la ecuación \( f(x) = 0 \), encontramos que \( x = 1 \) y \( x = 2 \) son los puntos donde la gráfica toca el eje. ¡Esa es la magia de las parábolas!

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