simpify \( \frac{4^{y} \cdot 2^{y+2}-8^{y}}{2^{2} \cdot 3^{0} \cdot 2^{3 y}} \)

Calculate or simplify the expression \( (4^y * 2^(y+2) - 8^y) / (2^2 * 3^0 * 2^(3*y)) \). Simplify the expression by following steps: - step0: Solution: \(\frac{\left(4^{y}\times 2^{y+2}-8^{y}\right)}{\left(2^{2}\times 3^{0}\times 2^{3y}\right)}\) - step1: Evaluate the power: \(\frac{\left(4^{y}\times 2^{y+2}-8^{y}\right)}{\left(2^{2}\times 1\times 2^{3y}\right)}\) - step2: Remove the parentheses: \(\frac{4^{y}\times 2^{y+2}-8^{y}}{2^{2}\times 1\times 2^{3y}}\) - step3: Multiply the terms: \(\frac{2^{3y+2}-8^{y}}{2^{2}\times 1\times 2^{3y}}\) - step4: Multiply the terms: \(\frac{2^{3y+2}-8^{y}}{2^{3y+2}}\) - step5: Subtract the terms: \(\frac{3\times 2^{3y}}{2^{3y+2}}\) - step6: Rewrite the expression: \(3\times 2^{-2}\) - step7: Evaluate the power: \(3\times \frac{1}{4}\) - step8: Multiply: \(\frac{3}{4}\) The simplified form of the expression \( \frac{4^{y} \cdot 2^{y+2}-8^{y}}{2^{2} \cdot 3^{0} \cdot 2^{3 y}} \) is \( \frac{3}{4} \) or 0.75.