Name. Q.2 Exit Thoket Solve. Show your work. \begin{tabular}{|c|c|}\hline\( x-6=23 \) & \( x+14=52 \) \\ \hline & \\ \hline\end{tabular}

To solve for \( x \) in the equations provided, let's tackle them one at a time. For the first equation \( x - 6 = 23 \): 1. Add 6 to both sides: \( x = 23 + 6 \) \( x = 29 \) For the second equation \( x + 14 = 52 \): 1. Subtract 14 from both sides: \( x = 52 - 14 \) \( x = 38 \) So, the solutions are: 1. From \( x - 6 = 23 \), \( x = 29 \) 2. From \( x + 14 = 52 \), \( x = 38 \) You have two different values for \( x \), suggesting each equation represents a different scenario or solution set. Be sure to clarify the context of these equations in practice! Sometimes, solving equations can lead to multiple solutions or no solutions at all, depending on how they're structured. It’s a good practice to double-check your arithmetic operations to avoid common pitfalls, like misplacing a negative sign or miscalculating an addition or subtraction. Keep aware of the specific requirements of the problem to ensure accurate outcomes!