b) \( \frac{8 x+2}{4}+\frac{6 x+7}{6}-\frac{9 x+11}{3} \)

To solve the expression \( \frac{8 x+2}{4}+\frac{6 x+7}{6}-\frac{9 x+11}{3} \), let's start by finding a common denominator for the fractions. The least common multiple of 4, 6, and 3 is 12. Now, we'll rewrite each term with a denominator of 12: - \( \frac{8x + 2}{4} \) becomes \( \frac{3(8x + 2)}{12} = \frac{24x + 6}{12} \) - \( \frac{6x + 7}{6} \) becomes \( \frac{2(6x + 7)}{12} = \frac{12x + 14}{12} \) - \( \frac{9x + 11}{3} \) becomes \( \frac{4(9x + 11)}{12} = \frac{36x + 44}{12} \) Now, we can combine the fractions: \[ \frac{24x + 6 + 12x + 14 - 36x - 44}{12} \] Combining the like terms in the numerator gives us: \[ \frac{(24x + 12x - 36x) + (6 + 14 - 44)}{12} = \frac{0x - 24}{12} \] So, this simplifies down to: \[ \frac{-24}{12} = -2 \] Therefore, the final result is: \[ \boxed{-2} \]