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\( 1< \) For the polynomial function \( f(x)=-4 x^{4}+8 x^{3} \), answer the parts a through e. a. Use the Leading Coefficient Test to determine the graph's end behavior. A. The graph of \( f(x) \) falls to the left and falls to the right. B. The graph of \( f(x) \) rises to the left and rises to the right. C. The graph of \( f(x) \) rises to the left and falls to the right. D. The graph of \( f(x) \) falls to the left and rises to the right. b. Find the \( x \)-intercepts. State whether the graph crosses the \( x \)-axis, or touches the \( x \)-axis and turns around, at each intercept. The \( x \)-intercept(s) is/are 0,2 . (Type an integer or a decimal. Use a comma to separate answers as needed. Type each answer only once.) At which \( x \)-intercept(s) does the graph cross the \( x \)-axis? Select the correct choice below and, if necessary, fill in the answer box to comi A. The \( x \)-intercept(s) at which the graph crosses the \( x \)-axis is/are (Type an integer or a decimal. Use a comma to separate answers as netded. Type each answer only once.) B. There are no \( x \)-intercepts at which the graph crosses the \( x \)-axis.

Ask by Page Peterson. in the United States
Mar 19,2025

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**a. End Behavior** The graph of \( f(x) = -4x^4 + 8x^3 \) falls to the left and falls to the right. **b. \(x\)-Intercepts and Behavior** The \(x\)-intercepts are at \(x = 0\) and \(x = 2\). At both intercepts, the graph crosses the \(x\)-axis.

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Beyond the Answer

The end behavior of the polynomial function \( f(x) = -4x^4 + 8x^3 \) is determined by its leading term, which is negative. As \( x \) approaches positive or negative infinity, the graph will fall in both directions. Thus, the correct choice is A: The graph of \( f(x) \) falls to the left and falls to the right. To find the \( x \)-intercepts, we solve \( f(x) = 0 \), leading to the equation \( -4x^4 + 8x^3 = 0 \). Factoring out \( -4x^3 \), we get \( -4x^3(x - 2) = 0 \). This gives us \( x = 0 \) and \( x = 2 \) as intercepts. The \( x \)-intercept at \( x = 0 \) has a multiplicity of 3, indicating the graph touches the axis and turns around, while at \( x = 2 \), with a multiplicity of 1, the graph crosses the axis. Therefore, the graph crosses the \( x \)-axis at 2 and touches it at 0. So, the intercepts are \( x = 0, 2 \) and it crosses at \( x = 2 \).

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