The data show the time in seconds, that members of a track team ran 100 meters: \( 10,11,10,9,19,11,11 \) - Identify the outlier. - Find the mean, median and mode. Mean- mode- Median- - Which measure of center is affected by the outlier?

**Step 1. Identify the Outlier** Given the data: \[ 10,\ 11,\ 10,\ 9,\ 19,\ 11,\ 11 \] We observe that all values are around 9–11, except \( 19 \). Thus, the outlier is: \[ \textbf{Outlier: } 19 \] **Step 2. Calculate the Mean** The mean is calculated by summing all values and dividing by the number of values. \[ \text{Sum} = 10 + 11 + 10 + 9 + 19 + 11 + 11 = 81 \] \[ \text{Number of values} = 7 \] \[ \text{Mean} = \frac{81}{7} \approx 11.57 \] **Step 3. Determine the Median** First, arrange the data in ascending order: \[ 9,\ 10,\ 10,\ 11,\ 11,\ 11,\ 19 \] Since there are 7 numbers (an odd amount), the median is the middle value (4th value): \[ \text{Median} = 11 \] **Step 4. Find the Mode** The mode is the value that appears most frequently. From the ordered data: \[ 9,\ 10,\ 10,\ 11,\ 11,\ 11,\ 19 \] The value \( 11 \) appears 3 times, which is more than any other value. Thus: \[ \text{Mode} = 11 \] **Step 5. Identify Which Measure of Center is Affected by the Outlier** The mean is calculated using all the data values; therefore, the high value \( 19 \) (the outlier) increases the overall sum, pulling the mean upward. In contrast, the median and mode are less affected since they depend on the order and frequency of values rather than their magnitude. \[ \boxed{\text{The mean is affected by the outlier.}} \] **Final Answers:** - **Outlier:** \( 19 \) - **Mean:** \( \approx 11.57 \) - **Median:** \( 11 \) - **Mode:** \( 11 \) - **Measure of center affected by the outlier:** Mean