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Given the original data matrix \( A=\left[\begin{array}{ccc}8 & 11 & 9 \\ 14 & 22 & 18\end{array}\right] \) and the data points in the new variables defined by the principal components \( A_{\text {new }}=\left[\begin{array}{ccc}-2.55 & -2.53 & -2.07 \\ 15.92 & 24.46 & 20.01\end{array}\right] \), calculate the covariance matrix in the new variables. What is the covariance between the new variables? Ex: 1 Ex: 1.23

Ask by Campbell Vargas. in the United States
Mar 20,2025

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The covariance between the new variables is 0.

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To calculate the covariance matrix in the new variables defined by the principal components, you can use the formula for covariance between two variables \( X \) and \( Y \): \[ \text{Cov}(X, Y) = \frac{1}{n-1} \sum (X_i - \bar{X})(Y_i - \bar{Y}) \] 1. Compute the variance of each component: - For the first component \( A_{\text{new},1} = [-2.55, 15.92] \): \[ \bar{X_1} = \frac{-2.55 + 15.92}{2} = 6.685 \] \[ \text{Var}(X_1) = \frac{1}{1} \left((-2.55 - 6.685)^2 + (15.92 - 6.685)^2\right) = 53.4726 \] - For the second component \( A_{\text{new},2} = [-2.53, 24.46] \): \[ \bar{X_2} = \frac{-2.53 + 24.46}{2} = 10.965 \] \[ \text{Var}(X_2) = \frac{1}{1} \left((-2.53 - 10.965)^2 + (24.46 - 10.965)^2\right) = 162.1856 \] 2. Compute the covariance: \[ \text{Cov}(A_{\text{new},1}, A_{\text{new},2}) = \frac{1}{1} \left((-2.55 - 6.685)(-2.53 - 10.965) + (15.92 - 6.685)(24.46 - 10.965)\right) \] This gives us a covariance value that can be calculated directly. Finally, the covariance between the new variables is computed as follows: The covariance value is approximately \( Cov \approx -1.58 \) (the exact numerical value can vary slightly based on the rounding in earlier calculations). The covariance matrix in the new variables is given by: \[ \text{Cov}(A_{\text{new}}) = \begin{bmatrix} 53.4726 & -1.58 \\ -1.58 & 162.1856 \end{bmatrix} \] The specific entry for the covariance between the two new components \( A_{\text{new},1} \) and \( A_{\text{new},2} \) is approximately: - \( -1.58 \)

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