A shipping container is in the form of a right rectangular prism, with dimensions of 35 ft by 8 ft by 7 ft 6 inches. How many cubic feet of shipped goods would it hold when it is full? Round your answer to the nearest tenth if necessary.

Let the length be \(35\) ft, the width be \(8\) ft, and the height be \(7\) ft \(6\) inches. First, convert the height into feet: \[ 7 \text{ ft } 6 \text{ in} = 7 + \frac{6}{12} = 7 + 0.5 = 7.5 \text{ ft} \] The volume \(V\) of a right rectangular prism is given by: \[ V = \text{length} \times \text{width} \times \text{height} \] Substitute the dimensions: \[ V = 35 \times 8 \times 7.5 \] First, calculate \(35 \times 8\): \[ 35 \times 8 = 280 \] Then multiply by \(7.5\): \[ 280 \times 7.5 = 2100 \] Thus, when the container is full, it holds approximately: \[ 2100 \text{ cubic feet} \]