A shipping container is in the form of a right rectangular prism, with dimensions of 35 ft by 8 ft by 7 ft 6 inches. How many cubic feet of shipped goods would it hold when it is full? Round your answer to the nearest tenth if necessary.

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Let the length be $$35$$ ft, the width be $$8$$ ft, and the height be $$7$$ ft $$6$$ inches. First, convert the height into feet:

$$
7 \text{ ft } 6 \text{ in} = 7 + \frac{6}{12} = 7 + 0.5 = 7.5 \text{ ft}
$$

The volume $$V$$ of a right rectangular prism is given by:

$$
V = \text{length} \times \text{width} \times \text{height}
$$

Substitute the dimensions:

$$
V = 35 \times 8 \times 7.5
$$

First, calculate $$35 \times 8$$:

$$
35 \times 8 = 280
$$

Then multiply by $$7.5$$:

$$
280 \times 7.5 = 2100
$$

Thus, when the container is full, it holds approximately:

$$
2100 \text{ cubic feet}
$$
The shipping container holds approximately 2,100 cubic feet of shipped goods when full.

A shipping container is in the form of a right rectangular prism, with dimensions of 35 ft by 8 ft by 7 ft 6 inches. How many cubic feet of shipped goods would it hold when it is full? Round your answer to the nearest tenth if necessary.

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