A group of people were asked if they had run a red light in the last year. 237 responded "yes", and 426 responded "no". Find the probability that if a person is chosen at random, they have run a red light in the last year. Give your answer as a fraction or decimal

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$$
\textbf{Step 1: Compute the Total Number of Responses}
$$
Adding the number of "yes" and "no" responses:
$$
237 + 426 = 663
$$

$$
\textbf{Step 2: Form the Probability Fraction}
$$
The probability that a randomly chosen person has run a red light is given by the fraction:
$$
\frac{\text{Yes responses}}{\text{Total responses}} = \frac{237}{663}
$$

$$
\textbf{Step 3: Simplify the Fraction}
$$
Divide the numerator and the denominator by their greatest common divisor. Both $$237$$ and $$663$$ are divisible by $$3$$:

$$
237 \div 3 = 79, \quad 663 \div 3 = 221
$$
Thus, the simplified fraction is:
$$
\frac{79}{221}
$$

$$
\textbf{Step 4: Express as a Decimal (Optional)}
$$
To express the probability as a decimal:
$$
\frac{79}{221} \approx 0.357
$$

$$
\textbf{Final Answer:}
$$
The probability that a person chosen at random ran a red light in the last year is:
$$
\frac{79}{221} \quad \text{or approximately} \quad 0.357.
$$
The probability is $$ \frac{79}{221} $$ or approximately 0.357.

A group of people were asked if they had run a red light in the last year. 237 responded "yes", and 426 responded "no". Find the probability that if a person is chosen at random, they have run a red light in the last year. Give your answer as a fraction or decimal

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