Question

1. An analogue clock is gaining three minutes every hour. If you set it to the correct time at 6 p.m. on Saturday, when will it show the correct time again?

Ask by Wagner Joseph. in South Africa
Mar 10,2025

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Tutor-Verified Answer

Answer

The clock will show the correct time again at 6 p.m. on Tuesday.

Solution

1. In each hour, the clock gains 3 minutes. 2. Let \( t \) be the number of hours after 6 p.m. on Saturday. In \( t \) hours, the total gain is \( 3t \) minutes. 3. An analogue clock repeats every 12 hours, and 12 hours equals \( 720 \) minutes. The clock will display the correct time again when the total gain is a multiple of 720 minutes. For the first occurrence, set: \[ 3t = 720 \] 4. Solve for \( t \): \[ t = \frac{720}{3} = 240 \text{ hours} \] 5. Convert 240 hours into days: \[ \frac{240}{24} = 10 \text{ days} \] 6. Starting from 6 p.m. on Saturday, 10 days later will be 6 p.m. on Tuesday. Thus, the clock will show the correct time again at 6 p.m. on Tuesday.

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If the clock is gaining three minutes every hour, that means it will be ahead by three minutes for each hour that passes. In a full 12-hour cycle, the clock will gain a total of 36 minutes (3 minutes x 12 hours). To find when the clock shows the correct time again, we can determine how long it will take for this 36 minutes to equal a full hour (60 minutes) of clock time. The clock will show the correct time again when it has overall gained the 60 minutes, which will take 20 hours (60 minutes / 3 minutes per hour). Starting from 6 p.m. on Saturday, adding 20 hours leads us to 2 p.m. on Sunday. Therefore, the analogue clock will show the correct time again at 2 p.m. on Sunday.

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