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3. The dimensions of a rectangle are 40 cm and 45 cm . If there is an error of \( 5 \% \) in the dimensions find the percentage error in calculating area of the rectangle. ( 3 mks )

Ask by Weaver French. in Kenya
Mar 15,2025

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The percentage error in calculating the area of the rectangle is approximately \(10.25\%\).

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To find the area of a rectangle, we use the formula \( A = \text{length} \times \text{width} \). Here, the length is 40 cm, and the width is 45 cm, giving an area of \( 1800 \, \text{cm}^2 \). With a \( 5\% \) error in each dimension, the error in length is \( 2 \, \text{cm} \) (which is \( 5\% \) of 40 cm) and in width is \( 2.25 \, \text{cm} \) (which is \( 5\% \) of 45 cm). When we calculate the area, the new dimensions become \( 42 \, \text{cm} \) and \( 47.25 \, \text{cm} \). The new area is approximately \( 1985.5 \, \text{cm}^2 \). Therefore, the error in area is \( 1985.5 - 1800 = 185.5 \, \text{cm}^2 \). To find the percentage error in area, we use the formula: \[ \text{Percentage Error} = \left( \frac{\text{Error}}{\text{Original Area}} \times 100\% \right) \] Plugging in the values, we get: \[ \text{Percentage Error} = \left( \frac{185.5}{1800} \times 100 \right) \approx 10.3\% \] So, the percentage error in calculating the area of the rectangle is approximately \( 10.3\% \).

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