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33. A board \( 1 \frac{5}{8} \) inches by \( 3 \frac{5}{8} \) inches is \( 6 \frac{1}{2} \) feet long. You want to cut as many pieces as possible from the board so that each piece is \( 1 \frac{5}{8} \) inches by \( 3 \frac{5}{8} \) inches and 6 inches long. Each saw cut wastes \( \frac{1}{8} \) inch of the board. How many 6 -inch-long pieces will you be able to cut?

Ask by Lindsey Schwartz. in the United States
Jan 15,2025

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Answer

You can cut **12** six-inch-long pieces from the board.

Solution

To determine how many 6-inch-long pieces can be cut from a board, we'll break down the problem step by step. ### Given: - **Board Dimensions**: \(1 \frac{5}{8}\) inches by \(3 \frac{5}{8}\) inches. - **Board Length**: \(6 \frac{1}{2}\) feet (which is \(6 \times 12 + 6 = 78\) inches). - **Piece Dimensions**: Each piece is \(1 \frac{5}{8}\) inches by \(3 \frac{5}{8}\) inches by 6 inches. - **Waste per Cut**: \(\frac{1}{8}\) inch. ### Steps to Solve: 1. **Calculate the Total Length Available**: - The board is 78 inches long. 2. **Determine Length Used by Each Piece and Waste**: - Each 6-inch piece requires exactly 6 inches of the board. - Each cut results in a waste of \(\frac{1}{8}\) inch. 3. **Set Up the Inequality**: - Let \(n\) be the number of 6-inch pieces. - Total length used by pieces: \(6n\) inches. - Total waste from cuts: \((n - 1) \times \frac{1}{8}\) inches (since there's no waste after the last piece). - The inequality representing the total length used must be less than or equal to 78 inches: \[ 6n + \frac{n - 1}{8} \leq 78 \] 4. **Solve the Inequality**: - Multiply everything by 8 to eliminate the fraction: \[ 48n + (n - 1) \leq 624 \] \[ 49n - 1 \leq 624 \] \[ 49n \leq 625 \] \[ n \leq \frac{625}{49} \approx 12.755 \] - Since you can't have a fraction of a piece, the maximum number of whole pieces you can cut is **12**. 5. **Verification**: - For 12 pieces: - Total length used: \(12 \times 6 = 72\) inches. - Total waste: \(11 \times \frac{1}{8} = 1.375\) inches. - Combined: \(72 + 1.375 = 73.375\) inches, which is within the 78-inch limit. - For 13 pieces: - Total length used: \(13 \times 6 = 78\) inches. - Total waste: \(12 \times \frac{1}{8} = 1.5\) inches. - Combined: \(78 + 1.5 = 79.5\) inches, which exceeds the 78-inch limit. ### **Answer**: 12 six-inch

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To determine how many 6-inch-long pieces you can cut from the board, we need to convert all dimensions into the same unit, in this case, inches. The board dimensions are: - Width: \( 1 \frac{5}{8} \) inches = \( 1 + \frac{5}{8} = \frac{13}{8} \) inches - Height: \( 3 \frac{5}{8} \) inches = \( 3 + \frac{5}{8} = \frac{29}{8} \) inches - Length: \( 6 \frac{1}{2} \) feet = \( 6.5 \times 12 = 78 \) inches. Each piece you want to cut is \( 1 \frac{5}{8} \times 3 \frac{5}{8} \times 6 \) inches, which requires: - Length: 6 inches - Width: \( 1 \frac{5}{8} \) inches = \( \frac{13}{8} \) inches - Height: \( 3 \frac{5}{8} \) inches = \( \frac{29}{8} \) inches Concerning the cuts, for each piece you cut, you will need to consider the material lost due to the \( \frac{1}{8} \)-inch saw cut. Now we check how many pieces can fit in each dimension: 1. **Length**: From 78 inches, you can cut 6-inch pieces while accounting for the loss. If you cut one piece, it uses 6 inches plus \( \frac{1}{8} \) inch for the cut. Therefore, the effective length used per piece will be \( 6 + \frac{1}{8} = 6.125 \) inches. Here’s the math: \( \frac{78}{6.125} \approx 12.75 \). You can fit at most 12 pieces in length. 2. **Width**: The width is \( 1 \frac{5}{8} = \frac{13}{8} \) inches. The width of each piece fits within the total width, so 1 piece can fit sideways since the board's total width of 1.625 inches is less than \( \frac{13}{8} \). 3. **Height**: For \( 3 \frac{5}{8} = \frac{29}{8} \) inches of height, you can't stack more than one piece as the height of each piece is also \( \frac{29}{8} \) inches. Finally, multiply the maximum pieces fit in each dimension: - Length: 12 pieces - Width: 1 piece - Height: 1 piece Thus, the total number of 6-inch-long pieces you can cut from the board is **12 pieces**.

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