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A line has a slope of 7 and passes through the point \( (-1,-8) \). Write its equation in slope- intercept form. Write your answer using integers, proper fractions, and improper fractions in simplest form.

Ask by Turnbull Long. in the United States
Jan 15,2025

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Tutor-Verified Answer

Answer

The equation of the line is \( y = 7x - 1 \).

Solution

To find the equation of a line with a slope of 7 that passes through the point \((-1, -8)\), we can use the **slope-intercept form** of a line, which is: \[ y = mx + b \] where: - \( m \) is the slope - \( b \) is the y-intercept Given: - Slope (\( m \)) = 7 - Point \((-1, -8)\) lies on the line Plugging the known values into the equation: \[ -8 = 7(-1) + b \] \[ -8 = -7 + b \] Solving for \( b \): \[ b = -8 + 7 \] \[ b = -1 \] Now, substitute \( m \) and \( b \) back into the slope-intercept form: \[ y = 7x - 1 \] **Final Answer:** \[ y = 7x - 1 \]

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Bonus Knowledge

To find the equation of the line in slope-intercept form \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept, we start with the slope, which is given as 7. We can use the point \( (-1, -8) \) to find \( b \). Using the point to substitute: \[ -8 = 7(-1) + b \] This simplifies to: \[ -8 = -7 + b \] Now, solving for \( b \): \[ b = -8 + 7 = -1 \] Therefore, the equation of the line in slope-intercept form is: \[ y = 7x - 1 \] It’s all set with integers ready to roll!

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