Evaluate these expressions using \( a=-4, b=2 \) and \( c=-7 \) \[ \begin{array}{ll}42+7=49 & \text { b } \frac{5 a b-4 c}{\sqrt[3]{2 a}}\end{array} \]

Let's evaluate the expressions step by step using the values \( a = -4, b = 2, c = -7 \). 1. **Evaluate the constant expression:** \[ 42 + 7 = 49 \] This is straightforward, and it evaluates to \( 49 \). 2. **Now, evaluate the expression:** \[ b \frac{5ab - 4c}{\sqrt[3]{2a}} \] First, substitute the values for \( a, b, c \): - Calculate \( 5ab \): \[ 5(-4)(2) = -40 \] - Calculate \( -4c \): \[ -4(-7) = 28 \] - Now, combine these: \[ 5ab - 4c = -40 + 28 = -12 \] Next, calculate \( \sqrt[3]{2a} \): - Calculate \( 2a \): \[ 2(-4) = -8 \] - Now, calculate the cube root: \[ \sqrt[3]{-8} = -2 \] Now, substitute these values back into the expression: \[ 2 \frac{-12}{-2} \] Simplifying this gives: \[ 2 \cdot 6 = 12 \] So the final evaluations are: \[ 42 + 7 = 49 \] \[ b \frac{5ab - 4c}{\sqrt[3]{2a}} = 12 \] Thus, the evaluated expressions are: 49 and 12.