Determine the amplitude, period, and phase shift of the function. Graph the function. \( y=-5 \cos (3 x+\pi) \) The amplitude is \( \square \). (Simplify your answer.) The period is \( \square \). (Type an exact answer, using \( \pi \) as needed. Use integers or fractions for any numbers in the expression.) The phase shift is \( \square \). (Type an exact answer, using \( \pi \) as needed. Use integers or fractions for any numbers in the expression.)
Upstudy AI Solution
Answer
Solution
Answered by UpStudy AI and reviewed by a Professional Tutor


Beyond the Answer
The amplitude of the function is the absolute value of the coefficient in front of the cosine, which is \(-5\). Thus, the amplitude is \(5\). The period of the cosine function is determined by the formula \( \frac{2\pi}{|b|} \), where \( b \) is the coefficient of \( x \). In this function, \( b = 3 \), so the period is \( \frac{2\pi}{3} \). The phase shift of the function can be calculated using the formula \( -\frac{c}{b} \), where \( c \) is the constant added to \( x \) in the cosine function. Here, we have \( c = \pi \) and \( b = 3 \), yielding a phase shift of \( -\frac{\pi}{3} \). Thus: - Amplitude: \( 5 \) - Period: \( \frac{2\pi}{3} \) - Phase Shift: \( -\frac{\pi}{3} \) For the graph of the function: It will be a cosine wave that starts at \(-5\) (due to the negative sign) at \(x = -\frac{\pi}{3}\), peaks at \(0\) after \(\frac{2\pi}{3}\), and then repeats. It’s like a dance with high peaks and low valleys, turning the standard cosine wave upside down!