Question
\( \sqrt[3]{(3 \times 4+4 \times 5)-(12 \div 3+20 \div 4)+2 \times 5-6} \) \( \begin{array}{lll}\text { A) } 5 & \text { B) } 4 & \text { C) } 3 \\ \text { D) } 2 & & \text { E) } 1\end{array} \)
Ask by Wood Munoz. in Peru
Mar 13,2025
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Answer
La respuesta es 3, que es la opción C.
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Mind Expander
Let's simplify the expression step by step! First, calculate the innermost operations: - \(3 \times 4 = 12\) - \(4 \times 5 = 20\) - So, \(12 + 20 = 32\) Next, calculate the divisions: - \(12 \div 3 = 4\) - \(20 \div 4 = 5\) - Now, \(4 + 5 = 9\) Now substitute theseinto the expression: \[ 32 - 9 + 10 - 6 \] Calculating this gives: - \(32 - 9 = 23\) - \(23 + 10 = 33\) - \(33 - 6 = 27\) Now take the cube root: \[ \sqrt[3]{27} = 3 \] So the answer is C) 3!