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\( (3+\sqrt{5}) \) and \( (3-\sqrt{5}) \)

Ask by Chadwick Morrison. in Nigeria
Jan 11,2025

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\( (3 + \sqrt{5}) \) and \( (3 - \sqrt{5}) \) are conjugate pairs of irrational numbers. They are roots of the equation \( x^2 - 6x + 4 = 0 \) and have properties like sum of 6, product of 4, and can be used in algebraic expressions and geometric interpretations.

Solution

The expressions \( (3 + \sqrt{5}) \) and \( (3 - \sqrt{5}) \) are **conjugate pairs** involving the square root of 5. These numbers have several interesting mathematical properties and applications. Here's a detailed overview: ### 1. **Basic Properties** - **Sum and Difference:** \[ \begin{align*} \text{Sum} &= (3 + \sqrt{5}) + (3 - \sqrt{5}) = 6 \\ \text{Difference} &= (3 + \sqrt{5}) - (3 - \sqrt{5}) = 2\sqrt{5} \end{align*} \] - **Product:** \[ (3 + \sqrt{5})(3 - \sqrt{5}) = 3^2 - (\sqrt{5})^2 = 9 - 5 = 4 \] - **Quotient:** \[ \frac{3 + \sqrt{5}}{3 - \sqrt{5}} = \frac{(3 + \sqrt{5})^2}{(3)^2 - (\sqrt{5})^2} = \frac{9 + 6\sqrt{5} + 5}{4} = \frac{14 + 6\sqrt{5}}{4} = \frac{7 + 3\sqrt{5}}{2} \] ### 2. **Roots of a Quadratic Equation** These two numbers are the roots of the quadratic equation derived from their sum and product. - **Quadratic Equation:** \[ x^2 - (\text{Sum})x + (\text{Product}) = 0 \implies x^2 - 6x + 4 = 0 \] Solving \( x^2 - 6x + 4 = 0 \) using the quadratic formula: \[ x = \frac{6 \pm \sqrt{36 - 16}}{2} = \frac{6 \pm \sqrt{20}}{2} = \frac{6 \pm 2\sqrt{5}}{2} = 3 \pm \sqrt{5} \] ### 3. **Irrationality** Both \( 3 + \sqrt{5} \) and \( 3 - \sqrt{5} \) are **irrational numbers** since they involve the square root of a non-square integer (5). ### 4. **Recurrence Relations and Powers** These numbers can be used to express terms in certain recurrence relations, especially those resembling the Fibonacci sequence. - **Powers:** The powers of \( (3 + \sqrt{5}) \) and \( (3 - \sqrt{5}) \) can be expressed using binomial expansion. Additionally, since they are roots of the quadratic equation \( x^2 = 6x - 4 \), higher powers can be simplified using this relation. - **Example:** \[ (3 + \sqrt{5})^2 = 9 + 6\sqrt{5} + 5 = 14 + 6\sqrt{5} = 6(3 + \sqrt{5}) - 4 \] This simplifies calculations involving higher powers. ### 5. **Geometric Interpretation** In the context of the quadratic equation \( x^2 - 6x + 4 = 0 \), the numbers \( 3 + \sqrt{5} \) and \( 3 - \sqrt{5} \) represent the points where the parabola \( y = x^2 - 6x + 4 \) intersects the x-axis. ### 6. **Applications** - **Algebraic Identities:** They are useful in simplifying expressions involving radicals. - **Number Theory:** These conjugate pairs appear in the study of quadratic fields and Diophantine equations. - **Geometry:** They can represent lengths, distances, or other geometric quantities that involve irrational numbers. ### 7. **Graphical Representation** If you plot these numbers on the real number line: - \( 3 + \sqrt{5} \) is approximately \( 3 + 2.236 = 5.236 \) - \( 3 - \sqrt{5} \) is approximately \( 3 - 2.236 = 0.764 \) They are symmetric around the center point 3. ### 8. **Conjugate Properties in Complex Numbers** While \( (3 + \sqrt{5}) \) and \( (3 - \sqrt{5}) \) are real numbers, the concept of conjugates extends to complex numbers, where conjugate pairs are of the form \( a + bi \) and \( a - bi \). These pairs share similar properties, such as having the same real part and opposite imaginary parts. --- If you have a specific question or application in mind regarding \( (3 + \sqrt{5}) \) and \( (3 - \sqrt{5}) \), feel free to ask for a more targeted explanation!

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The Deep Dive

Did you know that the numbers \( (3+\sqrt{5}) \) and \( (3-\sqrt{5}) \) are actually conjugates? This means they have a unique relationship where their sum is a rational number and their product yields another rational number. Specifically, the sum is \( 6 \) and the product is \( 4 \) (since \( (3+\sqrt{5})(3-\sqrt{5}) = 9 - 5 \)). This forms an important concept in algebra, especially when dealing with quadratic equations! In real-world applications, these types of conjugate pairs can arise in various fields including physics and engineering, particularly in situations involving quadratic equations, such as projectile motion and optimization problems. For example, if you're trying to determine the maximum height of a launched object, solving a quadratic equation leads you to expressions similar to these, allowing you to find critical points or beneficial parameters effectively!

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